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Algebra
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Find 2x2 - 2z4 + y2 - x2 + z4 if x = -4, y = 3, and z = 2. I've tried to do this over and over and I just can get it.
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\[2(-4)^2 - 2(2)^4 + 3^2 - (-4)^2 + 2^4\]all the terms with 16 in it cancel out
\[=2*16 - 2*16 + 9 - 16 + 16 = 9\]
Okay so the answer is 9? if so can you explain to me why?
all the terms with 16 are cancelled. 2*16 - 2*16 = 0 and the last 2 -16 + 16 = 0
equivalent to x^2 - z^4 + y^2 and x^2 = z^4
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Which make 9?
all thats left over is y^2 = 9
OHHH Okay :)
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