Question

Help!!!

Answer 1

Can someone explain this problem to me?

Answer 2

Solve this equation by Completing the Square.

Answer 3

\[x^2 + 6x -3=0\]

Answer 4

ever solved problem of completing the square before ?

Answer 5

nope

Answer 6

ok, 1st step,

Divide the co-efficient of 'x' by 2

whats the co-efficient of x here ?

Answer 7

6

Answer 8

yes!
so dividing it by 2 gives us 3, right ??

Now step 2:
Add 3 on both sides,
what do u get ?

Answer 9

\[x^2 =3\]

Answer 10

sorry :P
step 2 :
was to SQUARE the co-efficient!

so, do, 3^2 =...

Answer 11

9

Answer 12

what do i do next

Answer 13

sorry for late reply.

step 3 : was actually adding the answer of step 2 on both sides.

so,
\(\large x^2+6x+9 -3 =+9\)
got this ?

Answer 14

i think so

Answer 15

then add 3 on both sides to isolate
(x^2+6x+9)

do you notice anything about (x^2+6x+9) ?

Answer 16

\[x^2 +6x +6 =9\]

Answer 17

hmmm ya arnt i supposed to subtract the 9 and 3?

Answer 18

adding 3 on both sides first,
\(x^2+6x+9 = 3+9 \\ so, x^2+6x+9 = 12\)
got this ?

the whole point was to get, x^2+6x+9 ...which is a perfect square! (hence the name of the method is 'completing the square')

Answer 19

ohhhhhh

Answer 20

i got it now

Answer 21

thanks