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Mathematics 7 Online
OpenStudy (anonymous):

write in terms of sine only : 5(sin2x-cos2x)

OpenStudy (anonymous):

Trig identity!

OpenStudy (anonymous):

not very helpful

OpenStudy (anonymous):

Let me look it up on Google.

OpenStudy (anonymous):

http://www.sosmath.com/trig/Trig5/trig5/trig5.html

OpenStudy (anonymous):

A pair of commonly memorized trig identities are sin(2x) = 2sinxcosx cos(2x) = 1 - 2sin^2(x) One of them might be useful

OpenStudy (anonymous):

Do you know substitution by equality?

OpenStudy (anonymous):

yeah of course

OpenStudy (anonymous):

but what are we substituting ?

OpenStudy (anonymous):

Your question asks for everything in terms of sine right?

OpenStudy (anonymous):

So substitute everything that has cosine by something that has sine but that are of course equal as well.

OpenStudy (anonymous):

ok but 2sinxcosx is one term

OpenStudy (anonymous):

You should not substitute that ones once it will still give you a cosine.

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