The sum of three consecutive odd integers is –27. What are the numbers? A. {–7, –9, –11} B. {–10, –9, –8} C. {–5, –9, –13} D. {–11, –13, –15}
hint : any two adjacent odd numbers differ by 2
for ex, 3 and 5 are two adjacent odd numbers, they differ by 5-3 = 2
so, if u say below are the required odd numbers :- \(x-2,~ x,~ x+2\) then, since they add up to -27, we have :- \(x-2 + x + x+2 = -27\)
solve \(x\)
x has to be all the same number right ?
\(x-2 + x + x+2 = -27\) group like terms \(x+x+x -2 + 2 = -27\) \(3x = -27\) \(x = -9\)
so, the required numbers wud be :- \(x-2, ~x, ~x+2\) \(-9-2, ~-9, ~-9+2\) \(-11, ~-9, ~-7\)
see if that makes some sense
Yea it kinda makes sence, but where did this come from. x - 2, x, x + 2 ?
very good question :) notice that they're differing by "2" so they represent consecutive odd numbers
and can there be questions like this too ? The sum of three consecutive even integers is –27. What are the numbers? (change odd to even)
If it's consecutive even integers will it turn into like this. x - 1, x, x + 1?
let me ask u a different question first :)
consider sum of "3 even integers"
can the sum be ever odd ?
no
then, wat u asking is illegal right ?
The sum of three consecutive even integers is –27. What are the numbers? (change odd to even)
yea
sum of 3 even integers can never be odd, so nobody can find the numbers ;P
change ur question :)
You can forget about my last question, thank you :)
np :)
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