Question

6x-3y=3; (1,1), (-1,-3)

Answer 1

all this is, is plugging in the points so for (1,1) it's actually (x,y) right? so x=1 and y=1 now all you have to do is plug in points.
6x-3y=3
6(1)-3(1)=3
6-3=3
3=3
so this is correct. now onto the second set of points.
(-1,-3) is (x,y) so x=-1 and y=-3
6x-3y=3
6(-1)-3(-3)=3
-6+6=3
ok here i'm confused, is this what you wanted us to do?

Answer 2

yes and thank you!!