Question

7x^2-3x=0

Answer 1

Both terms have a gcf of x. Factor that out and you should be able to solve it.

Answer 2

can you show me how please

Answer 3

\(7x^2-3x=0 \rightarrow (7 \times x \times x) - (3 \times x) = 0\). Since both terms have at least one multiple of x, you can factor it out of both terms: \(x(7 \times x) - x(3) \rightarrow x(7x -3)=0 \). Can you figure it out from here?

Answer 4

no

Answer 5

7x^2-3x=0
x(7x-3)=0
so now we have 2 solutions;
x(7x-3)=0
7x-3=0/x
7x=3
x=3/7
OR x(7x-3)=0
x=0/(7x-3)
x=0
so the 2 solutions are: either 0 or 3/7

Answer 6

technically it is x= 0 and x=3/7. Because both work.

Answer 7

sorry solutions for x. so x = 0 or 3/7.

Answer 8

@BTaylor yeah that's what i meant. :)