Question

Find all roots of the equation z^2-j=0

Answer 1

Any guesses? What's the root of an equation?

Answer 2

z-1

Answer 3

I understand that it must be in the form of ax^2+bx+c=0
So does a=1, b=-1 and c=0?

Answer 4

Nope, it's:

a=1, b=0, c=-j

Answer 5

so then that is plugged into the quadratic equation?

Answer 6

sorry I meant to write:
\[\frac{ 2\sqrt{1j} }{ 2 }\]