Question

What is the cartesian form of r^2=theta

Answer 1

hmm
\(\large x^2+y^2=\tan^{-1} \frac{y}{x}\)

Answer 2

How could i simplify that. ?

Answer 3

u dnt need to simplify ( thats why using polar is better in this case)
\(\large \tan (x^2+y^2)=\frac{y}{x}\)
\(y=\large x\tan (x^2+y^2)\)

Answer 4

Ohh okay thanks (:

Answer 5

got it ?