Question

Please Help?? I don't understand how to do these, can someone please explain how to solve this?




Which of the following points is in the solution set of y < x^2 - 4x + 3?

(-3, 0)
(1, 0)
(2, -1)

Answer 1

There are more complicated and thorough ways to go about it, but for now, it is only an exercise in substitution.

Given: y < x^2 - 4x + 3
And the point: (1,0)

Simply substitute the given values and see if ti works.

(0) < (1)^2 - 4(1) + 3 -- We are trying to determine if this inequality is true.
0 < 1 - 4 + 3 -- Still not sure.
0 < -3 + 3 -- Maybe
0 < 0 -- No, that is false! (1,0) is NOT in the solution set.

Answer 2

Oh, ok :) I love substitution :) thank you! :)