Question

Identify the 42nd term of an arithmetic sequence where a 1 = -12 and a 27 = 66

Answer 1

It has to do with Arithmetic Sequences

Answer 2

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Answer 3

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Answer 4

\[

a_n=a_1+(n-1) r\\
a_{27} =-12 + 26 r=66\\
r=3\\
a_n=-12+3(n-1) \
\]
Can you find now \( a_{42}\)?

Answer 5

\[
a_{42}=12+ 3(41)=-12+ 123=111
\]