Question

Identify the graph of f(x) = 3|x + 2|.

Answer 1

y=|x| is a v shaped graph with a vertex at the orgin
if you have y=|x-2| we move the graph over to (2,0)
If you have y=|x+2| we move the graph over to (-2,0)


if you have y=a|x-2|, we turn the graph upside down if a is negative. We leave as a v if a is positive.

a will just be our left and right stretch.

Answer 2

but what points does it intersect through? @freckles

Answer 3

what do you mean? like we have the x-intercept.
If you want to find the y-intercept, you could set x=0 and solve for y.

Answer 4

y=3|x+2|
I gave you the x-intercept (-2,0)
Can you find the y-intercept?

Answer 5

http://static.k12.com/calms_media/media/1346000_1346500/1346439/1/889af048478a2c63e7a9ab1a67ed7fe5b42e7277/HS_A1G2_S2_116160a.jpg is that a proper graph for it? @freckles i dont understand this.

Answer 6

or this? http://static.k12.com/calms_media/media/1346000_1346500/1346442/1/10994073fd8f4fe47ccd014c0e506fe6c391fae1/HS_A1G2_S2_116160d.jpg @freckles

Answer 7

if x=0 what is y if y is given by 3|x+2|
Replace x with 0
so y intercept is 3|0+2| which equals?

Answer 8

6 @freckles

Answer 9

right so which graph do you think it looks like
the first one or the second one?
you know we have a v-shaped (not an upside down v since v is positive)
Just a V shaped.
And we know it goes through (-2,0) and (0,6)
which graph does that?

Answer 10

I think the first one. @freckles

Answer 11

the first one doesn't go through the y-axis at 6 does it?

Answer 12

no but how would we know if the other does? i just thought you meant it hits the 6 directly. @freckles

Answer 13

it does
but the 1st graph doesn't hit 6 it hits at 2
the other graph is going to hit somewhere above the 2 and 6 is greater than 2
so the 2nd graph would be more close to our graph

Answer 14

k thanks ill try that. @freckles

Answer 15

can you help me with 1 more? @freckles

Answer 16

http://static.k12.com/calms_media/media/1346000_1346500/1346468/1/6169cc83f1cb2465c8ade45ce3581a49403780e4/HS_A1G2_S2_116166.jpg
write an equation for the graphed function. it would be f(x)=|x - 3| right?

Answer 17

looks like a good answer :)