how can i find "b" in y=mx+b
y-mx=b
how to find it? y=mx+b <--- ^ is right here
ohhh you meant how to solve for "b"
well can you give me your eqaution so I can tell you
because I know how I just need to see your problem its very simple ill show you
Rearrange for B. Y=mx+b Y-mx=b Ex. Find the value of given: Y=2/3x+b and the point (1,2) Step 1: Substitute (1,2) into equation. 2=2/3(1)+B note: (1=x, y=2) Step 2: Simplify 2=2/3+B Step 3: Rearrange. 2 multiplied by 3 divided by 2= B 6/2=B 3=B
If you are given a graph, B is represented by the y-intercept which means the point that lies on the y-axis, this point will always have a x-value=0.|dw:1395100872023:dw|
@emilylaurenforever : Part of the difficulty we're all having here is that we don't know from you whether you're supposed to solve the given equation y=mx+b algebraically for b, or whether you have an actual linear equation and need to identify the value of b. Please provide this clarifying information.
|dw:1395101149816:dw| i know the slope of the line is 4/3 and the first part of my equation is y=4/3x+b i need to find the value of b
Thank you for sharing this. Without it I really had little or no idea of what you were trying to do. You're given two points and are asked to find the equation of the line thru these 2 points in slope-intercept form.
Write y = m x + b. Choose either of the 2 given points. For example, choose (3,0). Then when x = 3, y = 0. Substitute these x- and y- values into y=mx+b. Also substitute your value for the slope, m. Finally, solve the resulting equation for b. Mind trying this, and showing all work?
y = m * ( ) + b 0 = (?) * (3 ) + b You've found the slope, m; substitute its value above. Then solve this equation for b.
|dw:1395101694363:dw| ?
@mathmale did i do this correctly?
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