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Please help me How do I write Y-2=4(x+1) into point slope form And 2x+5y=15 Please help me and thank you
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I just don't get how to plug the numbers into the formula
\[y-2=4(x+1) \] distribute the \(4\) \[y-2=4x+4\] then add \(2\) \[y=4x+6\]
it is not a matter of plugging in to a formula there is no formula it is "solve for \(y\)"
But the question says write in point slope form
yes, what that means is "solve for \(y\)" to make it look like \[y=mx+b\] but it is not plugging in to a formula, it is using algebra to get \(y\) by itself on one side of the equal sign
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Oh ok thanks 😊 It's just algebra is very confusing to me
How would I solve 2x+5y=15 into slope intercept form
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