Question

mth

Answer 1

Sorry I don't know.

Answer 2

You should have an expansion for this situation.

Usually: \(\tan(A + B) = \dfrac{\tan(A)+\tan(B)}{1-\tan(A)\tan(B)}\)

Answer 3

...and you should know that \(\tan{\pi/3} = \dfrac{\sin(\pi/3)}{\cos(\pi/3)} = \dfrac{\sqrt{3}/2}{1/2} = \sqrt{3}\)

That's all the pieces you need.