Question

pleaseee help!
if you can at least help with one of them i would greatly appreciate it!

factor completely,
x^2+13x+36

factor completely,
a^2-a-20

factor completely,
x^2-5x-14

factor completely, b^2+12b+32

Answer 1

x^2+13x+36

what two number MULTIPLIED gives you 36 but ADDED to give you 13?

Answer 2

1) (x +9 )(x+4) because 4 *9 = 36 and 4+9 = 13

Answer 3

do you know the next one?

Answer 4

3) Factor: x^2 - 5x - 14?

(x-7)(x+2)= 0

x=7, x=-2

Answer 5

2) a^2 - a - 20 = a^2 - 5a + 4a - 20 = a (a-5) + 4(a-5) = (a+4)(a-5)

Answer 6

(a -5 ) (a+4) because -5+4=-1 and -5 * 4 = -20

Answer 7

4)
(b^2)+12b+32=0
=> (b^2)+8b+4b+32=0
=> (b+8)(b+4)=0
=> b= -8,-4.

Answer 8

3) (x-7)(x+2) because -7 +2 = -5 and -7 *2 = -14

Answer 9

thank you guys.
i have another one-

8y^2+6y+1

Answer 10

4) (b+4) (b+8) because 4+8 =12 and 4*8=32

Answer 11

thanks sooo much sorry these are alot of problems.

Answer 12

its fine

Answer 13

no problem.....i love math

Answer 14

haha that's good then i guess.
can you do 8y^2+6y+1 and explain how to

Answer 15

are we factoring it??

Answer 16

I think what needs to happen is you get explained on how to do these problems, not just supplied answers. That is not the purpose of this site...

Answer 17

i hope this is right...

8y^2 + 6y + 1

List the factors of a and c.
a: 1 x 8, 2 x 4
c: 1 x 1
Since c is positive find factors from the list that will add up to the absolute value of b.
1, 1, 2, and 4 -----> (1 x 2) + (1 x 4) = 6
Arrange these four factors accordingly. Because both b and c are positive, both parentheses will have a plus sign.
( + )( + )
Ask yourself, "Which two factors with y as a variable will multiply to give me 8y^2?" Fill in the parentheses.
(4y + )(2y + )
Use trial and error(by FOILing).
(4y + 1)(2y + 1)
Check answer.
(4y)(2y) = 8y^2
(4y)(1) = 4y
(2y)(1) = 2y
(1)(1) = 1
Set up as a polynomial.
8y^2 + 4y + 2y + 1
Combine like-terms.
8y^2 + 6y + 1

So 8y^2 + 6y + 1 is equal to (4y + 1)(2y + 1).

Answer 18

wow that was helpful lol. thank you

Answer 19

lol your welcome...

Answer 20

if you need help just ask ok

Answer 21

okay! thanks

Answer 22

@GamerGirl.1

15b^2-7b-2

Answer 23

15b^2 - 7b - 2
(5b + 1) (3b - 2)

Answer 24

thanks!
4a^2-8a-5

Answer 25

4a^2 - 8a - 5
(2a - 5) (2a + 1)

Answer 26

4y^2+25y+6

Answer 27

4y^2 + 25y + 6
(4y + 1) (y + 6)

Answer 28

omg thank you soo much! let me know if you ever need help with anything (except not math) lol

Answer 29

lol

Answer 30

lol im good at math