Question

Find the equation of a line that contains the point (2,-3) with a slope of 1/6.

Answer 1

y-y1=m(x-x1)

Answer 2

put [m=1/6 , y=-3 , x=2]

in
\[m=\frac{ y-y1 }{ x-x1}\]

Answer 3

@Abdulhameed

Answer 4

y-(-3) = 1/6(x-2)

y + 3 = 1/6(x -2)

y + 3 = 1/6x - 1/3
+3 +3

Solve: -1/3 + 3/1

Then put it in y = mx + b

You only need the y intercept