Question

verify

Answer 1

sqrt24

Answer 2

2sqrt6

Answer 3

nevermind lol got it

Answer 4

right

Answer 5

6/sqrt2

Answer 6

thats right, but the grader will give u 0 marks

Answer 7

why?

Answer 8

\(\huge \sqrt{\frac{36}{2}}\)


\(\huge \sqrt{18}\)


\(\huge \sqrt{9 \times 2}\)


\(\huge 3\sqrt{ 2}\)

Answer 9

grader likes this answer better^

Answer 10

genrally, dont leave radicals in the denominator.

Answer 11

if u simplify ur answer further by rationaliziing the denominator u wud get the same answer

Answer 12

even though it says rationalize the denominator

Answer 13

ok..

Answer 14

\(\large \frac{6}{\sqrt{2}}\)

Answer 15

rationalize the denominator and see wat u get

Answer 16

to rationalize, u need to multiply top and bottom by sqrt(2) right ?

Answer 17

I thought that's what it wanted, but if I go further it's 3sqrt2?

Answer 18

\(\large \frac{6}{\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}\)

\(\large \frac{6\sqrt{2}}{2} \)

\(\large 3 \sqrt{2}\)

Answer 19

yes, 3sqrt2 is the final ansur

Answer 20

Gotcha.. thank you

Answer 21

rationalizing denominator means, getting rid of radicals in the denominaotr

Answer 22

u wlc :)

Answer 23

Can I keep posting here?

Answer 24

go ahead

Answer 25

13sqrt2

Answer 26

right

Answer 27

\(\large \color{red}{\checkmark}\)

Answer 28

WOOO

Answer 29

This has me confused

Answer 30

for the stuff inside radical, write in powers of 4

Answer 31

81^4k^4(p^4)^30?

Answer 32

\(\large \sqrt[4]{81kp^{30}}\)


\(\large \sqrt[4]{3^4kp^{4*7+2}}\)

Answer 33

\(\large \sqrt[4]{81kp^{30}}\)

\(\large \sqrt[4]{3^4kp^{4*7+2}}\)

\(\large \sqrt[4]{3^4kp^{4*7}p^2}\)

\(\large \sqrt[4]{3^4k(p^{7})^4p^2}\)

Answer 34

Is the last line the answer?

Answer 35

nope

Answer 36

u seem to be in rush lol

Answer 37

I am lol I'm tired and want to finish

Answer 38

\(\large \sqrt[4]{81kp^{30}}\)

\(\large \sqrt[4]{3^4kp^{4*7+2}}\)

\(\large \sqrt[4]{3^4kp^{4*7}p^2}\)

\(\large \sqrt[4]{3^4k(p^{7})^4p^2}\)


\(\large 3p^7\sqrt[4]{kp^2}\)

Answer 39

And I still have 13 questions to finish lol

Answer 40

last line is the answer

Answer 41

thank you

Answer 42

2?

Answer 43

that 2? was what I think the answer is lol

Answer 44

\(\large \color{red}{\checkmark}\)

Answer 45

\(\large \sqrt[3]{192x^3y^5}\)

\(\large \sqrt[3]{64\times 3 x^3y^3y^2}\)

\(\large 4xy\sqrt[3]{3 y^2}\)

Answer 46

9/7?

Answer 47

\(\large \color{red}{\checkmark}\)

Answer 48

3sqrt5

Answer 49

\(\large \color{red}{\checkmark}\)

Answer 50

-(sqrtr-9sqrt5)sqrtr

Answer 51

\(\large -\sqrt{r}(\sqrt{r} - 9\sqrt{s})\)

\(\large -r + 9\sqrt{rs}\)

Answer 52

its the bottom one?

Answer 53

u just need to distribute

Answer 54

huh

Answer 55

lol u should sleep a bit and start math again after u wake up

Answer 56

first line is exactly same as ur question

Answer 57

lol i have to finish the last 8 questions

Answer 58

second line is the simplified form

Answer 59

:/

Answer 60

okay, stay alert few more minutes

Answer 61

40sqrt2?

Answer 62

14sqrt2? lol one of those

Answer 63

14sqrt2 is \(\large \color{red}{\checkmark}\)

Answer 64

22+2sqrt2 @ganeshie8

Answer 65

\(\large \color{red}{\checkmark}\)

Answer 66

4 more

Answer 67

3sqrt2?

Answer 68

@ganeshie8 I have 2 min left

Answer 69

\(\large \color{red}{\checkmark}\)

Answer 70

@vshiroky

Answer 71

Thank you :)

Answer 72

you're done ?