Question

Help please (question below) I will fan and medal.

Answer 1

What is the simplified from of
\[\sqrt{48n^9}\]

Answer 2

i am confused a bit can you explain? and it is sq.root of 48n^9

Answer 3

oh its 9? sorry i read it y!!! imma sorry!! :((

Answer 4

its okay i do admit it does look like a y at 1st

Answer 5

\[\sqrt{x^{2}} = x\]
\[\sqrt{xy}= \sqrt{x} \times \sqrt{y}\]

so using these we can solve the problem
N.B.
48 = 3x16 = 3(4^2)
n^9 = n(n^8) = n(n^4)^2

can you try now ?

Answer 6

ya umm
\[\sqrt{6.9n^3} * \sqrt{6.9n^3}\]

Answer 7

my choices are this tho

\[A.) 4n^3 \sqrt{3}\]
\[B.) 4n^4 \sqrt{3n}\]
\[C.) 3n \sqrt{4n^8}\]
\[D.) 4 \sqrt{3n^9}\]

Answer 8

@kewlgeek555

Answer 9

\[\sqrt{48n^{9}} = \sqrt{48}\sqrt{n ^{9}}\]
\[\sqrt{48} = \sqrt{16 \times 3} = \sqrt{4^{2} \times 3} = 4\sqrt{3}\]
\[\sqrt{n^{9}} = \sqrt{n^{8} \times n} = \sqrt{(n^{4})^{2} \times n} = n ^{4}\sqrt{n}\]

Answer 10

so what would you get if you combine them ?

Answer 11

\[4n^4 \sqrt{3n}\] right?

Answer 12

correct

Answer 13

thanks for helping me out

Answer 14

any time :)