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Algebra 19 Online
OpenStudy (rissyroo118):

helpppppp????? The sum of two consecutive integers is at least 36. What is the least possible pair of integers? 16 and 17 17 and 18 18 and 19 19 and 20

OpenStudy (anonymous):

The two numbers have to add up to 36 or higher.

OpenStudy (rissyroo118):

c 18 &19 @ConDawg

OpenStudy (anonymous):

Sorry, I should have said, which one doesn't add up to 36 OR HIGHER.

OpenStudy (rissyroo118):

its okay lol i figured this one out.

OpenStudy (anonymous):

Alright, what did you get?

OpenStudy (aayushi.somani):

let the 2 consecutive no.'s be x and x+1 so , X + (x+1) >36 2x+1>36 2x>35 so , x >17.5 so the no's will be 16 and 17

OpenStudy (rissyroo118):

Solve the inequality. 2 + |t + 6| < 12 t > 4 or t < –11 t < 4 and t > 11 –16 < t < 4 –4 < t < 16

OpenStudy (aayushi.somani):

option A @rissyroo118

OpenStudy (rissyroo118):

Solve the equation. |k + 9| = 4 {–13, –5} {–5, 5} {–5, 13} {all real numbers greater than or equal to –13 and less than or equal to –5}

OpenStudy (aayushi.somani):

option D

OpenStudy (rissyroo118):

Which expression is equivalent to |b| >6? b > –6 and b < 6 b < –6 or b > 6 b > –6 or b < 6

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