How do I solve t^2+t-28=0, I'm doing Completing the Square.

Question

anonymous · Answer

Do you know how to complete the square?

anonymous · Answer

yeah, but I am having trouble factoring out the answers...

anonymous · Answer

@shatteredskittlez  where r u getting stuck at ?
would u like to show your work?

anonymous · Answer

Sure!
t^2+t-28=0
         +28  +28
t^2+t=28
                 Now I would square the 1 in 1t (bx in the equation)
                  (1/2)^2
                  0.5^2
                  0.25
t^2+t+0.25=28+0.25
thta was as far as i got before i got confused on factoring my answer...

anonymous · Answer

@shatteredskittlez u r going right
continuing from where u left
(t+0.5)^2 = 28.25

anonymous · Answer

i used the identity (a+b)^2 = a^2 + 2*a*b+ b^2

anonymous · Answer

ah ok! thx for ur help! :D Problem solved!