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What basic trigonometric identity would you use to verify that sinx cosx tanx=1-cos^2x
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@burgandy Hint 1:- tanx = sinx/cosx HInt2 :- sin^2x+cos^2x = 1
would it be sinx=cosx tanx?
Change the tanx to be in terms of sin and cos... can you do that? @burgandy
I can't. :(
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\[sinx*cosx*\frac{ sinx }{ cosx }\] u can cancel cosx so u will get sinx*sinx which is sin^2x
\[tanx = \frac{ sinx }{ cosx }\]
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