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Mathematics 19 Online
OpenStudy (anonymous):

f(x) = x e^(-x). find concave up or down

OpenStudy (ipwnbunnies):

Use what we told you. Find the critical numbers. Use the Second Derivative Test to find concavity.

OpenStudy (anonymous):

second derivative is (e^(-x)) (-2+x) whats next , how i find the numbers

OpenStudy (ipwnbunnies):

Hmm, from what I know, you find the critical numbers by setting the first derivative equal to 0.

OpenStudy (ipwnbunnies):

Solve for x. Then use the SDT.

OpenStudy (anonymous):

ok so first i find critical numbers ?

OpenStudy (ipwnbunnies):

That;s what I would do. Anyone else got another strategy, that doesn't involve graphing? lol

OpenStudy (anonymous):

-e^(-x) (-1+x) = 0

OpenStudy (anonymous):

cant find critical numbers with this eq

OpenStudy (anonymous):

is critical number 1 ?

OpenStudy (ipwnbunnies):

Yes lol. That would be the only one since an exponential function cannot equal 0.

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