Mathematics
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OpenStudy (anonymous):
I know what the answer is, but I don't know how to show my work. METALS!!!
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OpenStudy (anonymous):
\[\sqrt{30}\times \sqrt{50}\]
OpenStudy (anonymous):
\[10\sqrt{15}\]
OpenStudy (anonymous):
I just need help with showing the work.
OpenStudy (kc_kennylau):
1. Combine the surds
OpenStudy (anonymous):
?
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OpenStudy (kc_kennylau):
\[\sqrt a\sqrt b=\sqrt{ab}\]
OpenStudy (anonymous):
\[10\sqrt{15}\] is the answer
OpenStudy (kc_kennylau):
I know...
OpenStudy (kc_kennylau):
The first step is to combine them into one thing
OpenStudy (anonymous):
I thought the first step was to simplify each irrational number so that you can put them together.
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OpenStudy (kc_kennylau):
Well that also works
OpenStudy (kc_kennylau):
But mine would be faster
OpenStudy (kc_kennylau):
Yours would be easier
OpenStudy (anonymous):
ok. Then show me how to do it your way
OpenStudy (kc_kennylau):
\[\sqrt{30}\sqrt{50}=\sqrt{30\times50}=\sqrt{1500}=\sqrt{15\times100}=10\sqrt{15}\]
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OpenStudy (anonymous):
does that work for all equations?
OpenStudy (kc_kennylau):
*surds
OpenStudy (kc_kennylau):
And yes
OpenStudy (anonymous):
thx. can you show me the other way so I can compare?
OpenStudy (kc_kennylau):
\[\sqrt{30}\sqrt{50}=\sqrt{30}\sqrt{2\times25}=5\sqrt{30}\sqrt2=5\sqrt{60}=5\sqrt{15\times4}=10\sqrt{15}\]
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OpenStudy (anonymous):
How did you get \[\sqrt{30} \sqrt{2\times25} = 5\sqrt{30} \sqrt{2}\]
OpenStudy (kc_kennylau):
\[\sqrt{30}\sqrt{2\times25}=\sqrt{30}\sqrt2\sqrt{25}=5\sqrt{30}\sqrt2\]
OpenStudy (anonymous):
can you plz explain it?
OpenStudy (anonymous):
oh. nevermind
OpenStudy (anonymous):
I don't get the last step
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OpenStudy (kc_kennylau):
\[5\sqrt{15\times4}=5\sqrt{15}\sqrt4=5\sqrt4\sqrt{15}=5\times2\sqrt{15}=10\sqrt{15}\]
OpenStudy (anonymous):
oh. thank you so much!
OpenStudy (kc_kennylau):
no problem, any more questions?
OpenStudy (anonymous):
not right now. thx again!
OpenStudy (kc_kennylau):
again, no problem