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Mathematics 19 Online
OpenStudy (anonymous):

I know what the answer is, but I don't know how to show my work. METALS!!!

OpenStudy (anonymous):

\[\sqrt{30}\times \sqrt{50}\]

OpenStudy (anonymous):

\[10\sqrt{15}\]

OpenStudy (anonymous):

I just need help with showing the work.

OpenStudy (kc_kennylau):

1. Combine the surds

OpenStudy (anonymous):

?

OpenStudy (kc_kennylau):

\[\sqrt a\sqrt b=\sqrt{ab}\]

OpenStudy (anonymous):

\[10\sqrt{15}\] is the answer

OpenStudy (kc_kennylau):

I know...

OpenStudy (kc_kennylau):

The first step is to combine them into one thing

OpenStudy (anonymous):

I thought the first step was to simplify each irrational number so that you can put them together.

OpenStudy (kc_kennylau):

Well that also works

OpenStudy (kc_kennylau):

But mine would be faster

OpenStudy (kc_kennylau):

Yours would be easier

OpenStudy (anonymous):

ok. Then show me how to do it your way

OpenStudy (kc_kennylau):

\[\sqrt{30}\sqrt{50}=\sqrt{30\times50}=\sqrt{1500}=\sqrt{15\times100}=10\sqrt{15}\]

OpenStudy (anonymous):

does that work for all equations?

OpenStudy (kc_kennylau):

*surds

OpenStudy (kc_kennylau):

And yes

OpenStudy (anonymous):

thx. can you show me the other way so I can compare?

OpenStudy (kc_kennylau):

\[\sqrt{30}\sqrt{50}=\sqrt{30}\sqrt{2\times25}=5\sqrt{30}\sqrt2=5\sqrt{60}=5\sqrt{15\times4}=10\sqrt{15}\]

OpenStudy (anonymous):

How did you get \[\sqrt{30} \sqrt{2\times25} = 5\sqrt{30} \sqrt{2}\]

OpenStudy (kc_kennylau):

\[\sqrt{30}\sqrt{2\times25}=\sqrt{30}\sqrt2\sqrt{25}=5\sqrt{30}\sqrt2\]

OpenStudy (anonymous):

can you plz explain it?

OpenStudy (anonymous):

oh. nevermind

OpenStudy (anonymous):

I don't get the last step

OpenStudy (kc_kennylau):

\[5\sqrt{15\times4}=5\sqrt{15}\sqrt4=5\sqrt4\sqrt{15}=5\times2\sqrt{15}=10\sqrt{15}\]

OpenStudy (anonymous):

oh. thank you so much!

OpenStudy (kc_kennylau):

no problem, any more questions?

OpenStudy (anonymous):

not right now. thx again!

OpenStudy (kc_kennylau):

again, no problem

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