Probability
18 Online
OpenStudy (anonymous):
x + (10/x-2) = x^2+3x/x-2 solve for x...
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OpenStudy (fibonaccichick666):
Let's make sure we have the right problem first: is this it?\[x + \frac{10}{x-2} = \frac{x^2+3x}{x-2}\]
OpenStudy (anonymous):
yes!
OpenStudy (fibonaccichick666):
alrighty so do you have any ideas on how to start?
OpenStudy (anonymous):
nope..
OpenStudy (fibonaccichick666):
ok, how about we start by making the left sdie one big fraction. Can we do that?
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OpenStudy (fibonaccichick666):
Can you* do that for me please?
OpenStudy (anonymous):
do i make it say x+10/x^2-2?
OpenStudy (fibonaccichick666):
uhm not quite, tell me what you did there
OpenStudy (anonymous):
i added x to the top and bottom of the fraction. what was i suppose to do?
OpenStudy (fibonaccichick666):
Rules for fractions say this: \[\frac{a}{b}+\frac{c}{d}=\frac{ad+cb}{bd}\]
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OpenStudy (anonymous):
ok so i cross multiply then multiply the denominator?
OpenStudy (fibonaccichick666):
no, you multiply each by 1/1 to get a common denominator
OpenStudy (fibonaccichick666):
d/d and b/b =1 hence you can do that
OpenStudy (anonymous):
ok im following along
OpenStudy (fibonaccichick666):
so tell me what you get
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OpenStudy (anonymous):
lets swap answers.. lets see what you got first lol
OpenStudy (fibonaccichick666):
nope
OpenStudy (fibonaccichick666):
that's not how I help