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lim [e^(x+1)-x+2]/x x->-infinity
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I always struggle with these but I think its -1 e^(x + 1) ---> 0 21 can be neglected so we are left with INF / - INF = -1
You're right the answer is -1 but INF/-INF is indetermination
I need a correct judgement
yes you are correct I did these last year in my degree course and always struggled with them
would applying l'hopital s rule help here , - just a suggestion
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l'hospital rule is not working
just split it up\[\lim_{x\to-\infty}{e^{x+1}\over x}-\frac{x+2}x\]
thanks
welcome :)
still puzzled...
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first term goes to zero, second breaks up into -1-2/x
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