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why does the equation -2√(x+3)+2 =10 have an extraneous solution but the equation 2√(x+4) =4 does not
Because that thing before the square root is negative in the first case
I already knew that, but I am having problems figuring out why it makes its solution extraneous
Because if you continue it'd be \(\sqrt{x+3}=-4\)
Square root of a number can't be negative
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but when you square both sides of the equation x + 3 = 16
Therefore it'll produce an extraneous solution
Because the square of a negative number is positive
I get it now, thank you for your help
no problem
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