Question

Write an equation of the form y=a sin b x or y=a cos b x to describe the graph below

Answer 1

so recall that graph for sine... that'd be the simpler one

notice our graph
one "hump" and then one "burrow" thus we have 1 period
notice where it ends

Answer 2

the amplitude should be pretty obvious I'd think

Answer 3

the amplitude is 2

Answer 4

\[y=2\sin \left( 2\pi x \right)?\]

Answer 5

right. and we have a period of 1.. so we know that thus far we'd have \(\bf y=2sin(\square x)\qquad \cfrac{2\pi}{\square }=period\implies \cfrac{2\pi}{\square }=1\implies 2\pi=\square
\\ \quad \\
\implies y=2sin(2\pi x) \)

there are no phase shifts that I can tell, or vertical shifts

http://fooplot.com/#W3sidHlwZSI6MCwiZXEiOiIyc2luKDIqcGkqeCkiLCJjb2xvciI6IiNEOTFBMUEifSx7InR5cGUiOjEwMDAsIndpbmRvdyI6WyItMi4zODA1OTUxOTk5OTk5OTkyIiwiMi45NDQyMDQ3OTk5OTk5OTk2IiwiLTEuMTQ2ODgiLCIyLjEyOTkyMDAwMDAwMDAwMDMiXX1d