Question

Precal help

Answer 1

Convert the equation to polar form.
\[5x=5y\]

Answer 2

\(\bf x=rcos(\theta)\qquad y=rsin(\theta)
\\ \quad \\
5x=5y\implies x=y\implies rcos(\theta)=rsin(\theta)\implies r[cos(\theta)-sin(\theta)]=0\)

what do you think?

Answer 3

Well, I got to that but.. This online program says its wrong. Idk what the answer would be.

Answer 4

so.. what did you get?

Answer 5

I got that same r(costheta - sintheta)=0

Answer 6

I'd think that'd give r = 0

Answer 7

Its incorrect :/

Answer 8

Why do you think that gives just r=0?

Think about the line x=y, what are the properties of this lines in terms of radius and angle with respect to the origin?

Answer 9

I honestly do not know how to go about this anymore.