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OpenStudy (anonymous):
Assume we have a jar that contains 2 blue marbles, 2 red marbles, 2 green marbles, 2 yellow marbles, 2 white marbles, and 2 black marbles. If we randomly sample 2 marbles from this jar without replacement what is the probability of drawing a red or green marble on the first and a black or white marbles on the second?
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OpenStudy (anonymous):
4 / 12 x 4 / 11
OpenStudy (anonymous):
1/3 and 4/11 sorry
OpenStudy (anonymous):
Pr(1st is red or green) x Pr(2nd is black or white) 4 of 12 are red or grn 4 of the remaining 11 are black or white MULTIPLY them 4/12 x 4/11 = 4/33 or 0.1212
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