Question

how to find x-intercept only of this function?

Answer 1

f(x) = 7arctan(x+1) – ln(x^2 + 2x + 2)

Answer 2

\[7\tan(x+1)-\ln(x^2+2x+2)=0\]

\[7\tan(x+1)=\ln(x^2+2x+2)\]
by inspection \[x=-1\]
works since both sides give zero

Answer 3

Wow thanks! I thought i had to do some other to make the function zero. Thank you so much!

Answer 4

NOTE:we shud not assume this as the only zero ,there might be a lot of other possibilities,we wud have to work harder to show that this is the only zero

Answer 5

What would I need to do to find the other zero's?