Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

Help *metals*

OpenStudy (anonymous):

If y varies directly as x, find the constant of variation if y = 32 when x = 8.

OpenStudy (anonymous):

what is the formula for direct variation?

OpenStudy (anonymous):

first write the direct variation equation: y = kx. plug in what you know and solve for what you need.

OpenStudy (anonymous):

the formula is y=kx so plug in 32 for y and 8 for x.

OpenStudy (anonymous):

This answer is 4?

OpenStudy (anonymous):

you got it!

OpenStudy (anonymous):

yes!

OpenStudy (anonymous):

k=4

OpenStudy (anonymous):

Next question

OpenStudy (anonymous):

Write an appropriate direct variation equation if y = 14 when x = -14.

OpenStudy (anonymous):

you should have an idea of what to do, so do it!

OpenStudy (anonymous):

what is the formula for direct variation?

OpenStudy (anonymous):

y=kx right?

OpenStudy (anonymous):

yes, now get to it

OpenStudy (anonymous):

yes now plug in 14 for y and -14 for x and that is you're answer

OpenStudy (anonymous):

so what is you're answer?

OpenStudy (anonymous):

k=-x is that the answer

OpenStudy (anonymous):

no, that would mean the \(y=-x^2\)

OpenStudy (anonymous):

y=x ?

OpenStudy (anonymous):

14=k(-14)

OpenStudy (anonymous):

no, 14 = k(-14) solve for k

OpenStudy (anonymous):

-1

OpenStudy (anonymous):

yes!

OpenStudy (anonymous):

yep!

OpenStudy (anonymous):

k=-1

OpenStudy (anonymous):

y = 14x y = -14x y = x y = -x (options)

OpenStudy (anonymous):

what is -1*x

OpenStudy (anonymous):

if k=-1 then what you're answer?

OpenStudy (anonymous):

y=-1*x = ?

OpenStudy (anonymous):

y=-1x

OpenStudy (anonymous):

yes I believe so.

OpenStudy (anonymous):

Write an appropriate direct variation equation if y = 8 when x = 2.

OpenStudy (anonymous):

I'm done you can do that one on you're own since you know the formula.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!