please help
Rewrite 1−cos135 sin135 using a half-angle identity.
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OpenStudy (anonymous):
Rewrite 1−cos135/sin135 using a half-angle identity.
OpenStudy (zehanz):
Do you know any formulas for half angles?
OpenStudy (zehanz):
BTW, your original question is different from the second
OpenStudy (anonymous):
cos^2 X= 1/2(1+cos(2X))
sin^2 x= 1/2(1-cos(2X))
OpenStudy (anonymous):
yeah it's the second one
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OpenStudy (anonymous):
tan^2 X= 1-cos(2X)/1+cos(2X)
OpenStudy (zehanz):
This problem seems a bit far-fetched to me, because the exact values of this particular sin and cos are easily found.
You might know them: \(\cos 135°=-\frac{1}{2}\sqrt{2}\), \(\sin 135°=\frac{1}{2}\sqrt{2}\),
So the answer is 1 - - 1 = 2.
I cannot see how half-angle formulas would be of help here...
OpenStudy (anonymous):
because it has to be re written
OpenStudy (anonymous):
thank you anyways
OpenStudy (zehanz):
OK, I will give it a try...(might take a few minutes)
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