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\[2 \sin 4x=\sqrt{3}\] for 0<=x<=2pi
Solve this equation please
We can't help with tests, breh.
It's review for a test
Likely story.
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Should've put that in your original post sly boy. Hint: Use a special triangle you should've learned.
@iPwnBunnies Right so I ended with 60 degrees and 120 degrees. But my answer key says that the answers are pi/12 +n pi, and pi/6 + n pi. Not really sure where to go
Yeah, because the argument is 4x, not just x. And use radians, not degrees.
Ah the classic forgot to divide by 4. Thanks
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