Question

help with problem on law of sines

Answer 1

I know for sure that there are 2 possible answers

Answer 2

Apply the sine rule

a/sin A=b/sin B=c/sin C

Answer 3

I do but I keep messing up some how, I think it might be the rounding.

Answer 4

Can you show your work?

Answer 5

it's a lot, 37.7/sinA = 31.5/sin34^degree sign24'

ANGLE A=37.7xsin34^degreesign24'/31.5
sin inverse =42.54 equals the angle of A

180-42.54=137.46 A'

Answer 6

Why did you take 180-sin inverse angle?

Answer 7

REFERENCE ANGLE

Answer 8

It's okay i have to go, it's due already.

Answer 9

If you get A, you can find and angle C
as C=180-A-B

Answer 10

Then you can find c again using sine rule

Answer 11

it's just the primes that get me messed up: A' B' C'

Answer 12

Sorry I dont understand what A' B' C' are.