Please show steps so I understand this thoroughly.. (: Thanks! Find the product. (x - nu)(9x + 3nu)
Do you know the FOIL method?
hey ipwnbunnies
Not fairly well, however I could probably pickup on it.. If you guide me through it.
Have you done any quadratic equation stuff? Like, if you had (x+2)(x+3), can you expand it out?
Wouldn't that be x^2+5?
Not quite. It'll be x^2 + 5x + 6. Hold on.
Check out this little lesson: http://www.mathsisfun.com/definitions/foil-method.html
follow the distributive law
The page is blank for me @iPwnBunnies =[
9x^2+3xnu-9xnu-3n^2x^2 9x^2-6xnu-3n6@u^2 i doubled check and this is correct
9x^2-6xnu-3n^2u^2
i tripled checked to make sure
Okay, let me check to see if I do this right though... So.. (x - nu)(9x + 3nu) x * 9x = 9x^2 x * 3nu = 3nux ? -nu * 9x = -9nux -nu * 3nu = -3nu Is that all right?
No, I'm wrong. Check your last product.
no -nu*3nu=-3(nu)^2
Oh .. Whoops lol.
So now.. 9x^2 + 3nux - 9 nux + -3nu^2 9x^2 -6nux - 3nu^2 ?? Right
no -3n^2u^2 thats why i used parenthesis last time. to tell you that both the n and the u are squared
Oh. Ok. Are they correct @iPwnBunnies ?
What Bsho posted is correct. You just messed up the 'L' in FOIL. the last term should be -3*n^2*u^2
Now, add up the terms to get your answer.
So instead it would be 9x^2 - 6nux -3n^2u^2 ?
that is correct
Correct, good job.
Thank you @iPwnBunnies and @Bsho1997 :)
your welcome
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