Can someone help me with Standard forms given slope and a point?

Question

rock_mit182 · Answer

@MrsDavidRandle what is the problem ?

anonymous · Answer

38. slope = -2/5 ; (3, -9)
y+9=-2/5(x-3)
And then I'm stuck on getting-2/5*-3

anonymous · Answer

$$\large y-\color{red}{y_1}=\color{blue}m(x-\color{green}{x_1})$$

anonymous · Answer

lets try that again 
$$\large -\frac{2}{5}\times (-3)=\frac{2\times 3}{5}$$

anonymous · Answer

So 6/5

anonymous · Answer

yes

anonymous · Answer

y+9=-2/5+6/5
Do I subtract by 9 on both sides first or do I multiply everything by 5 first?

anonymous · Answer

depends on what form you want it in

anonymous · Answer

if you want it to look like 
$$y=mx+b$$ then subtract $9$
if you want it to look like 
$$ax+by=c$$ then multiply by $5$

anonymous · Answer

Okay I want the second one so does it look like this after I multiply by 5
5y+45=-2x+6 ?
then it would be 2x+5y=39 ?

anonymous · Answer

close but  you made a mistake at the end

anonymous · Answer

$$5y+45=-2x+6 ?$$ add $2x$ get 
$$12x+5y+45=6$$ then you need to SUBTRACT  $45$

anonymous · Answer

oops i meant 
$$2x+54+45=6$$ sorry

anonymous · Answer

2x+5y=-39?