OpenStudy (anonymous):

Let’s assume that the speed of a typical racing car can be recorded to an accuracy of 0.001 kph. Assuming the track distance is known to an accuracy of 0.01 km, is the uncertainty principle violated for a 1-tonne car? Why or why not?

4 years ago
OpenStudy (anonymous):

No, it's not. Strictly speaking, in terms of position and momentum, the uncertainty principle says:$\Delta x \Delta p \ge \frac{ ħ }{ 2 }$ Given that substitute your values: $\Delta x = 0.01km = 10m$$\Delta p = 1 tonne*0.001kph = 1000kg *0.00028m/s = 0.28kg∙m/s$$\Delta x \Delta p = 10m*0.28kg∙m/s = 2.8kg∙m ^{2}/s$$\frac{ ℏ }{ 2 } = 1.055*10^{-34}kg∙m ^{2}/s$So, you end up with an uncertainty 2*10^34 times greater than the Uncertainty Principle requires. All is well with Heisenberg. This case points out that generally violations of the Uncertainty Principle are not a concern in the macro world.

4 years ago
OpenStudy (anonymous):

thanks, it's really helpful

4 years ago