Question

need help graphing parallel lines

Answer 1

where are u stuck ?

Answer 2

everywhere dont know what to do

Answer 3

just two things u need to knw :
1) parallel lines will have same slope
2) point-slope form of line : \(y-y_1 = m(x-x_1)\)

Answer 4

you're asked to find the equation of line that runs thru \((-2, 1)\),
and goes parallel to another line whose equation is \(2x+3y = -10\)

Answer 5

knw how to find "slope" if you're given equation of a lien ?

Answer 6

*line

Answer 7

y=-2x-10

Answer 8

good try :) but who ate the "3" that was attached to "y" ?

Answer 9

\(2x+3y = -10\)

\(3y = -2x -10\)

Answer 10

right ?

Answer 11

divide both sides by 3

Answer 12

y=-2/3x-10/3

Answer 13

yes, so slope = ?

Answer 14

-2/3

Answer 15

so we have slope, \(m = -2/3\)
and we knw a point \((-2, 1)\)

Answer 16

can we write equation of this new line ?

Answer 17

use point slope form :

\(y - y_1 = m(x-x_1)\)

Answer 18

y+2=-2/3(x-1)

Answer 19

try again,
u have swapped \(x_1\) and \(y_1\)

Answer 20

point \((-2, 1)\)
\(x_1\) \(y_1\)

Answer 21

y-1=-2/3(x+2)

Answer 22

\(\large \color{red}{\checkmark}\)

Answer 23

good job !

Answer 24

thanks this is easy with ur help!

Answer 25

glad to hear :) u wlc !