Use summation notation to write the series 2.2+6.6+11+.. for 5 terms Note: In each of these images, the lower limit of the summation notation is either "n=1" or "n=0".
\[\sum_{n=0}^{4}2.2 + 4.4n\]
2.2 + 4.4*0 + 2.2 + 4.4*1 + 2.2 + 4.4*2 + 2.2 + 4.4*3 + 2.2 + 4.4*4 2.2 6.6 11 .......................
is it -22+4.4n
\[\sum_{n=0}^{4}2.2\left( 2n+1 \right)\]
Thanks
You can't read what I wrote? My summation expression says 2.2 + 4.4n
so it is 5 instead of 4
but that is not one of the choice
There are many different ways to answer. Didn't know it was multiple choice. My way is one. Surjithayer's is another. Plus there are others
If they give you answer choices...the easiest way is probably to try each one to see which one give you 2.2 6.6 11 etc
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\[\sum_{n=1}^{5}\left\{ 2.2+\left( n-1 \right)4.4 \right\}\]
ok that is what I have but it is a negative -2.2
\[\sum_{n=1}^{5}-2.2+4.4n\]
yes
\[=\sum_{n=1}^{5}\left\{ 2.2-4.4+4.4n \right\}=\sum_{n=1}^{5}\left( -2.2+4.4 n \right)\]
Thank you
@surjithayer LOL...How many ways can we think of??
ok
there are so many ways. All are correct.
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