Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

Help please. Fan & medal Pre calc

OpenStudy (anonymous):

Solve : 3x^2 + 5x + 13 = 0 Use Quadratic formula= -b +/- √b^2 - 4ac/2a

OpenStudy (anonymous):

I got -5 +/- √-131/6 is this correct?

OpenStudy (anonymous):

Or can you simplify

OpenStudy (ranga):

That is it.

OpenStudy (nincompoop):

you still have to solve

OpenStudy (anonymous):

No that is all its asking for as long as you cant simplify it

OpenStudy (ranga):

\[\Large x = \frac{ -5 + \sqrt{131} }{ 6 }~or~\frac{ -5 - \sqrt{131} }{ 6 }\]

OpenStudy (anonymous):

Thanks

OpenStudy (ranga):

If it wants answer in decimal, then you can use your calculator. Otherwise leave it as is.

OpenStudy (anonymous):

-5+-sqrt(25^2-4(3)(13))/(2(3)) -5+-sqrt(469)/(6)

OpenStudy (ranga):

sorry, i missed the negative sign. So there has to be an "i" outside the square root.

OpenStudy (ranga):

\[\Large x = \frac{ -5 + i\sqrt{131} }{ 6 }~or~\frac{ -5 - i\sqrt{131} }{ 6 }\]

OpenStudy (anonymous):

yes thats it haha :)

OpenStudy (anonymous):

that is not right ranga

OpenStudy (anonymous):

I forgot my i too

OpenStudy (ranga):

@clydesdalecup , b = 5 which when squared is 25. You have squared 25 instead.

OpenStudy (anonymous):

ahh nice catch

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!