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OpenStudy (anonymous):
Help please. Fan & medal
Pre calc
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OpenStudy (anonymous):
Solve : 3x^2 + 5x + 13 = 0
Use Quadratic formula= -b +/- √b^2 - 4ac/2a
OpenStudy (anonymous):
I got -5 +/- √-131/6 is this correct?
OpenStudy (anonymous):
Or can you simplify
OpenStudy (ranga):
That is it.
OpenStudy (nincompoop):
you still have to solve
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OpenStudy (anonymous):
No that is all its asking for as long as you cant simplify it
OpenStudy (ranga):
\[\Large x = \frac{ -5 + \sqrt{131} }{ 6 }~or~\frac{ -5 - \sqrt{131} }{ 6 }\]
OpenStudy (anonymous):
Thanks
OpenStudy (ranga):
If it wants answer in decimal, then you can use your calculator. Otherwise leave it as is.
OpenStudy (anonymous):
-5+-sqrt(25^2-4(3)(13))/(2(3))
-5+-sqrt(469)/(6)
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OpenStudy (ranga):
sorry, i missed the negative sign. So there has to be an "i" outside the square root.
OpenStudy (ranga):
\[\Large x = \frac{ -5 + i\sqrt{131} }{ 6 }~or~\frac{ -5 - i\sqrt{131} }{ 6 }\]
OpenStudy (anonymous):
yes thats it haha :)
OpenStudy (anonymous):
that is not right ranga
OpenStudy (anonymous):
I forgot my i too
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OpenStudy (ranga):
@clydesdalecup , b = 5 which when squared is 25. You have squared 25 instead.
OpenStudy (anonymous):
ahh nice catch
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