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Mathematics 14 Online
OpenStudy (anonymous):

how do you find the slope of the tangent ?

OpenStudy (zzr0ck3r):

take the derivative, then plug in 1

OpenStudy (anonymous):

thats it?!

OpenStudy (anonymous):

thanks!

OpenStudy (zzr0ck3r):

well take the derivative then plug in (1,1) your derivative will contain y's and x's

OpenStudy (anonymous):

is it -5/4 then?

OpenStudy (anonymous):

-1.25 in decimal it was correct ty!

OpenStudy (zzr0ck3r):

\(x^3+2xy+y^2=4 at (1,1) \(3x^2+2(y+xy')+2yy'=0\\3x^2+2y+2xy'+2yy'=0\\y'=\frac{-3x^2-2y}{2x+2y}\) \) yes

OpenStudy (anonymous):

:) thanks for writing that out,

OpenStudy (zzr0ck3r):

np

OpenStudy (zzr0ck3r):

wow my latex skills failed me, but you got it without it anyway:)

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