Write as a single logarithm
3log(x-2) - 2log(x-1)

Question

Write as a single logarithm
3log(x-2) - 2log(x-1)

anonymous · Answer

Do you know any of the log rules? If not I'll introduce them =)

anonymous · Answer

I know some of them, I just dont fully understand them

anonymous · Answer

$$a \log x=\log x^a$$

anonymous · Answer

$$\log m-\log n=\log \frac{ m }{ n }$$

anonymous · Answer

Yup, @surjithayer got here before me. Can you see how to use that in your question? Once you have that bit sorted we can look at merging them into one logarithm.

anonymous · Answer

so is it log(x-2)^3 / log(x-1)^2?

anonymous · Answer

or log (x-2)^3 over (x-1)^2

jdoe0001 · Answer

http://www.chilimath.com/algebra/advanced/log/images/rules%20of%20exponents.gif <--- use rule 3 listed there, then rule 2

anonymous · Answer

$$\log \frac{ \left( x-2 \right)^3 }{\left( x-1\right)^2 }$$

anonymous · Answer

okay perfect thanks for the help guys. I am also trying to find the value of log5 (13^5). I am not sure how to calculate it or the steps involved

anonymous · Answer

Refer back to the first equation @surjithayer posted.