Solve this equation for r: (2+3)r – 6 = 31
5-6=31
Distributing that r would work, but to my mind it'd be far more efficient NOT to distribute the r. We want to isolate r, not have r in several terms.
(2+3)r – 6 = 31 May I suggest adding 6 to both sides, to further isolate that r?
im sorry im trying i never done these
You're familiar with adding a number to both sides of an equation?
add 6 to 5?
Thank you for contributing, @Ludwig457.
What I see is (2+3)r-6=31. If you combine 2 and 3, you get 2+3 = 5. Thus, (2+3)r=5r, and 5r-6 = 31. +6= +6 ------- --- Please complete this work.
By inspection: r = (31+6)/5
Couldn't agree more! But I sense that @LaBlueEyes2013 would appreciate a step-by-step approach the first time through a problem such as this one.
(2+3)r – 6 = 31 1. combine 2 and 3: 2+3 = 5, and so (2+3)r = 5r 2. rewrite the equation as 5r - 6 = 31. 3. Add 6 to both sides and simplify the resulting equation.
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