Question

the plane through (-1 , 2 , -5) that is perpendicular to the planes 2x-y+z=1 and x+y-2z=3.

Answer 1

@ganeshie8 please solve this too .

Answer 2

cross the normals of given planes,
you will get the normal of required plane

Answer 3

normal of required plane = \(\left<2, -1, 1\right> \times \left<1, 1, -2\right>\)

Answer 4

since u knw a point on plance already, you're done.

Answer 5

okay thanks :)

Answer 6

u wlc !