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\[\int\limits_{0}^{1} (3x-2)^2 dx\]
I can think of two possible approaches here. (There may be more.) 1) use the substitutions u = 3x-2 and du=3dx, or 2) expand (3x-2)^2, using the binomial theorem or the FOIL method), and then integrate each term of the resulting polynomial, one at a time. Your choice!
i'll try the second one
I think the first method is the easier, but by all means go ahead with the second one if you like. I need to rest a while, but will be back. Happy to work with you, and looking forward to the next occasion!
ok thank you
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