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Find three consecutive even integers such that the sum of the first integer and three times the third integer is 64 more than the second integer
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If you assume n is the smallest of the even integers, how could you write the next two interns of n, since they are 2 and 4 units away, respectively?
hint: letting n be the first even integer, then the next is n+2, what would the next be?
Supoose the smallest integer is 18, the using zzr0ck3r's expression the next integer would be 18 +2 = 20. What is the third of the integers in terms of n?
I get the point thanks
Can you set-up the equation?
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n+3(n+4)=n+66
Yes!!! you are right. I must be getting punchy!
Now you are set. Solve for n, then complete the sequence.
Thanks for your help
You are welcome.
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