Question

Passing through the point(5,-2) and parallel to x+5y+5=0. Write in general equation.

Answer 1

Find the slope first, slope = -A/B in Ax+By+C=0

Answer 2

parallel => slope2=slope1 ffrom the irst equation: y=-1/5x-1 => slope 1 = -1/5. =>slope2=-1/5
=> equation2: y=-1/5x+C, we don't know what is C, but we know that when x=5 y=-2 (passing through the point (5-2)), so -2=-1/5*5+C => C=-2+1=-1
=> y=-1/5x-1 and in general equation: x+5y+5=0

Answer 3

ur required equation is
y-y1=m(x-x1)

Answer 4

m=-1/5
x1=5
y1=-2

Answer 5

true)

Answer 6

I dont understand why y=-1/5x-1 equals to x+5y+5=0. Explain? :)

Answer 7

u know an equation of a line is
y=mx+c
here m= slope of a line

Answer 8

if u compare ur given line, u will get
m=-1/5

Answer 9

@JC99

Answer 10

@JC99, y=-1/5x-1 equals y+1/5x+1=0 yes? and it equals 5y+x+5=0 (multiplying by five) equals x+5y+5=0 that's why y=-1/5x-1 equals to x+5y+5=0 - these are just different records