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OpenStudy (anonymous):
Solve for x: −3|2x + 6| = −12
A) x = 1 and x = 5
B) x = −1 and x = −5
C) x = −9 and x = 3
D) no solution
I got x = 5, x = -5.
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OpenStudy (solomonzelman):
div both sides by -3
OpenStudy (anonymous):
divide through by -3
OpenStudy (anonymous):
equate left side to plus/minus right side
OpenStudy (anonymous):
and then I have (2x + 6) = -4
im using parenthesis as absolute value signs
OpenStudy (solomonzelman):
hold on! -12 divided by -3 equals what ?
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OpenStudy (anonymous):
It would be 2x + 6 = -4 or 2x + 6 = 4
OpenStudy (anonymous):
ohhhh, I forgot 3 was negative! hold on
OpenStudy (anonymous):
-12 divided by -3 is 4
OpenStudy (solomonzelman):
yes
OpenStudy (solomonzelman):
\(\Huge\color{blue}{ \sf |2x + 6| = 4 }\)
\(\Huge\color{blue}{ \sf 2x + 6 = 4 }~~~~or~~~~\)\(\Huge\color{blue}{ \sf 2x + 6 = -4 }\) solve each equation
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OpenStudy (anonymous):
then I get 5 and negative 5.....like what I had in the first place
OpenStudy (anonymous):
2x = 4-6 = -2
OpenStudy (solomonzelman):
hold on, what do you get for the first equation where the 4 is positive?
OpenStudy (texaschic101):
2x + 6 = 4
2x = 4 - 6
2x = -2
x = -1
2x + 6 = -4
2x = -4 - 6
2x = -10
x = -5
OpenStudy (anonymous):
ohhh, I did that the wrong way around. thank you I get it now
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