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OpenStudy (yanasidlinskiy):
Factor by grouping.
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OpenStudy (yanasidlinskiy):
\[3x^2+7x\]
OpenStudy (yanasidlinskiy):
I need the steps to the final answer.
OpenStudy (yanasidlinskiy):
Ther's a -6 at the end.
hartnn (hartnn):
\( 3x^2+7x-6 \)
can you tell me 2 numbers whose sum is +7 and product is 3*6 = 18 ?
hartnn (hartnn):
***
can you tell me 2 numbers whose sum is +7 and product is 3*(-6) = -18 ?
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OpenStudy (yanasidlinskiy):
it would be 3 and 4????? idk.never learned this.
hartnn (hartnn):
what are factors of 18 ?
OpenStudy (yanasidlinskiy):
1,2,3,6,9,18
hartnn (hartnn):
so we need the sum as +7
how about taking 9 and -2 ??
sum = +7 and product = 9*-2 = -18 !
got how to find such 2 numbers here ?
hartnn (hartnn):
so we split +7x as \(\large +9x-2x\)
\(\large 3x^2+9x-2x-6\)
try to factor out +3x from first 2 terms, what u get ?
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OpenStudy (yanasidlinskiy):
How would I do that??
hartnn (hartnn):
\(\Large 3x(x+3) -2 (x+3)\)
here, i also factored -2 from last 2 terms.....did u get this step ?
OpenStudy (yanasidlinskiy):
OMG...you are so smart!!...yes i got this step!
hartnn (hartnn):
now we can factor out (x+3) entirely.
\(\large (x+3) [3x -2]\)
so your final factored form will be
\(\Large (x+3)(3x-2)\)
thats it!
OpenStudy (yanasidlinskiy):
Thank you so much!!!! Your're the the best!!!!!
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hartnn (hartnn):
You're welcome ^_^
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