Question

factor: xy+2y-x-2

Answer 1

(y-1)(x+2

Answer 2

(y-1)(x+2) i forgot the parentheses

Answer 3

You can do this by factoring by grouping:

\[xy + 2y - x - 2\]\[(xy + 2y) - 1(x+2)\](note that the sign of the 2 changed when I factored out the -1\)
Now factor each group:
\[y(x+2) -1(x+2)\]Notice that \((x+2)\) is a factor of both terms? Factor it out:
\[(x+2)(y-1)\]Now check your work by multiplying:
\[(x+2)(y-1) = x(y-1) + 2(y-1) = x*y -x*1 + 2*y -2*1 = xy - x + 2y -2 \]\[\qquad= xy + 2y - x - 2\]So the factoring is correct.